110=16t^2+4t+85

Solution for 110=16t^2+4t+85 equation:

110=16t^2+4t+85

We move all terms to the left:

110-(16t^2+4t+85)=0

We get rid of parentheses

-16t^2-4t-85+110=0

We add all the numbers together, and all the variables

-16t^2-4t+25=0

a = -16; b = -4; c = +25;
Δ = b2-4ac
Δ = -42-4·(-16)·25
Δ = 1616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1616}=\sqrt{16*101}=\sqrt{16}*\sqrt{101}=4\sqrt{101}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{101}}{2*-16}=\frac{4-4\sqrt{101}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{101}}{2*-16}=\frac{4+4\sqrt{101}}{-32}
$